Math, asked by Shubham2759Y, 11 months ago

Convert plane 2x+3y+4z=5 into a perpendicular and find its cosines.​

Answers

Answered by gaya3123
0

Step-by-step explanation:

Given equation of the plane

2x+3y+4z=5

divide with √a square+ b square+ c square

√1+4+4=3 on both sides

2/3x+3/3y+4/3z=5/3

2/3x+y+4/3z=5/3

which is of the form lx+my+nz=p

where (l,m,n) are D.C's of the plane

DC's of normal plane(l,m,n)=(2/3,1,4/3)

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