Convert sin theta + sin 8theta into product
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Answer:
We have,
sin12θ+sin4θ
⇒sin2(6θ)+sin2(2θ)
⇒2sin6θcos6θ+2sin2θcos2θ
⇒2sin2(3θ)cos6θ+4sinθcosθcos2θ
⇒4sin3θcos3θcos6θ+4sinθcosθcos 20
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