Question

convert sinA into form of cot A

Answer 1

i hope u understood my friend

Answer 2

cos A = 1 / sec A = 1 / √(1 + tan2A) = 1 / √(1 + 1/cot2 A) = 1 / √[(cot2 A + 1)/cot2 A)]  = 1 / √[(cot2 A + 1)] / (cot A) = (cot A) / √[(cot2 A + 1)] 
Therefore, cos A in terms of cot A is (cot A) / √[(cot2 A + 1)].