Question

convert the complex number -1-i in polar form​

Answer 1

Answer:

1+i

Step-by-step explanation:

Here, in complex form, z=-1+i

So, r=lzl=$\sqrt{(-1)^{2}+(-1)^{2} }$=$\sqrt{1+1}$=$\sqrt{2}$

θ=tan⁻¹[(-1)(-1)]

 =tan⁻¹(1)

 =π/4

a=r cosθ=$\sqrt{2}$x(1/$\sqrt{2}$)=1

b=r sinθ=$\sqrt{2}$x(1/$\sqrt{2}$)=1

so, in polar form, z=r(cosθ+i sinθ)

                              =$\sqrt{2}$[(1/$\sqrt{2}$)+i x (1/$\sqrt{2}$)]

                              =$\sqrt{2}$x[(1+i)/$\sqrt{2}$]

                              =1+i

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