convert the complex number in standard form z= 1+7i/(2-i)²
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Answer:
13/41 + (35/41)i
Step-by-step explanation:
We have,
1 + 7i/(2-i)^2
= 1 + 7i/(4 + 1 - 4i)
=1 + 7i(5 + 4i)/(5^2-4i^2)
=1 + (35i - 28)/(25 + 16)
= 1 - 28/41 + (35/41)i
= 13/41 + (35/41)i
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