Question

Convert the following: (a) 54.75 g/L HCI to molarity; (b) 3 M K2SO4 to g/L.​
Can somebody answer asap?​

Answer 1

Answer:

(a) 1.5 M

(b) 522 g/L

Explanation:

(a) 54. 75 g/L HCl = 54.75 g of HCl in 1 L of solution

No. of moles of HCl = 54.75/36.45= 1.5 moles

Molarity = no. of moles of solute/volume of solution ( in L)

Therefore Molarity = 1.5 /1 = 1.5 M

(b)

3 M $K_2SO_4$ = 3 moles of  $K_2SO_4$ in 1 L of solution

Mass of  $K_2SO_4$  = 3 × 174g = 522g

Therefore 3 M  $K_2SO_4$  = 522 g /L

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