Convert the following and write the chemical equations:
(a) An alcohol to an alkene
(b)An acid to an ester
Answers
Answer:
a)The reagent alcoholic KOH is used for the preparation of alkenes as it is dehydrohalogenation reaction. After halogenation action of alcoholic KOH forms Alkenes again not alcohols.
b)Carboxylic acids react with diazomethane to produce methyl esters. Because of the high reactivity of diazomethane, it is produced in-situ and then immediately reacted with the carboxylic acid to produce the methyl ester.
Explanation:
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Answer:
(a) Dehydration to alkenes
Converting an alcohol to an alkene requires removal of the hydroxyl group and a hydrogen atom on the neighbouring carbon atom. Because the elements of water are removed, this reaction is called a dehydration.
(b) Conversion of carboxylic acids to esters using acid and alcohols (Fischer Esterification) Description: When a carboxylic acid is treated with an alcohol and an acid catalyst, an ester is formed (along with water). This reaction is called the Fischer esterification. Notes: The reaction is actually an equilibrium.