Convert the following function into POS form?
F(A,B,C) = AB'C' + A'BC.
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By Idempotence law, we know that
([ABC + ABC)] + ABC) = (ABC + ABC) = ABC
Now the function F = A’BC + AB’C + ABC ‘ + ABC
= A’BC + AB’C + ABC’ + ([ABC + ABC)] + ABC)
= (ABC + ABC ‘) + (ABC + AB’C) + (ABC + A’BC)
= AB (C + C ‘) + A (B + B’)
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