Convert the following statements into linear equations:-
i) Half a number plus six is 11.
ii) The ratio of 2 numbers is 3:4 and the sum is 28.
iii) A car travels at a speed of 5 km/hr from Bhopal to Indore. After the journey of 3 hours, Indore is still 65 km away. Express the distance from Bhopal to Indore using variable 's'.
iv) If 15 is subtracted from half of a number the result is ten.
v) Sum of three consecutive multiples of 8 is 888.
vi) Twice of a number added to half a number equals to 25, Find the number.
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With steps plz....
Answers
Answered by
5
Hey friend here is your answer
Note - for all the variables , I am taking value C
1 . 1/2X. + 6 = 11
2 3X+4y=28 { here we need two variables as there are two d/f no.s}
3. Doubtful
4. 1/2X-15= 10
5. X+X+8+X+16=888
6. 2X+1/2Y= 25
Hope it helps you
Note - for all the variables , I am taking value C
1 . 1/2X. + 6 = 11
2 3X+4y=28 { here we need two variables as there are two d/f no.s}
3. Doubtful
4. 1/2X-15= 10
5. X+X+8+X+16=888
6. 2X+1/2Y= 25
Hope it helps you
see I am not sure of it that's why I didn't give
but I can tell basic hint take speed X distance and time is given you will get an equation
Answered by
0
Answer:
1) let the number be x.
half of x=1/2x
now add six= 1/2x+6=11
2)Let the common multiple be x
so the numbers are 3x and 4x
a.t.q, 3x+4x=28
3) let the distance from Bhopal to Indore be 's'
Speed of car=5km/hr
Still Indore is 65km
total distance=s+65km
time=3 hrs
therefore, s+65km=5km/3hrs
4)Let the number be x
A.T.Q,
1/2x-15=10
5)Let the first number be x
second number=x+8
third number=x+16
so, x+(x+8)+(x+16)=888
6) Let the number be x
a.t.q. , 2x+1/2x=25
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