Convert the given dialogue into indirect speech . The dialogue has both declarative and interrogative sentences : Dave : Libby , aren't the invitation cards for the dinner ready ? Libby : I sent them out to the various schools last week . Dave : Have you got any responses ? Libby : More than 70 people have accepted the invitation . Dave : Do you think there will be a good turnout ? Libby : I think we will have a crowd of about 200 .
Answers
2x-3y =12________(1)
2x +4y = -2_______(2)
Value of x & y
Subtract equ(1) &equ(2)
➡ -3y - 4y = 12 + 2
➡-7x = 14
➡x = 14/(-7)
➡x = -2
Keep value of x in equ(1)
➡2 × -2 - 3y = 12
➡-3y = 12 + 4
➡-3y = 16
➡y = 16/(-3)
➡y = -16/3
Value of x = -2
Value of y = -16/3
_________________
Keep Value of x & y in equ(1)
➡2 × -2 - 3 × -16/3 = 12
➡-4 + 16= 12
➡12 = 12
L.H.S. = R.H.S.
We can say that our solution is right.
_________________
\Large{\underline{\underline{\mathfrak{\red{\bf{Solution}}}}}}
Solution
\Large{\underline{\mathfrak{\orange{\bf{Given}}}}}
Given
2x-3y =12________(1)
2x +4y = -2_______(2)
\Large{\underline{\mathfrak{\orange{\bf{Find}}}}}
Find
Value of x & y
\Large{\underline{\underline{\mathfrak{\red{\bf{Explanation}}}}}}
Explanation
Subtract equ(1) &equ(2)
➡ -3y - 4y = 12 + 2
➡-7x = 14
➡x = 14/(-7)
➡x = -2
Keep value of x in equ(1)
➡2 × -2 - 3y = 12
➡-3y = 12 + 4
➡-3y = 16
➡y = 16/(-3)
➡y = -16/3
\Large{\underline{\mathfrak{\orange{\bf{Hence}}}}}
Hence
Value of x = -2
Value of y = -16/3
_________________
\Large{\underline{\underline{\mathfrak{\red{\bf{Answer\:Verification}}}}}}
AnswerVerification
Keep Value of x & y in equ(1)
➡2 × -2 - 3 × -16/3 = 12
➡-4 + 16= 12
➡12 = 12
L.H.S. = R.H.S.
We can say that our solution is right.
_________________