Question

convert the given expression in canonical sop form, y = ac + ab + bc​

Answer 1

Convert the given expression in canonical sop form, y = ac + ab + bc​:

Explanation:

Y (A, B, C) = AB + BC + CA,

• this expression is a SOP expression, on account that we notice the Boolean feature has 3 literals A, B and C, so each term of the Boolean expression need to include all of the 3 literals to transform it into canonical SOP form.

Hence, = Y (A, B, C) = AB + BC + CA

            = AB. (C + C) + BC.

Answer 2

Given,

Y = AC+AB+BC

To Find,

canonical SOP form of the given expression.

Solution,

Each term of the expression must contain all the three literals to convert it into canonical SOP form. therefore,

AC+AB+BC= AC.(B+B (bar))+ AB.(C+C(bar))+BC.(A+A(bar))

                  =ABC+A.B(bar).C+ABC+AB.C(bar)+ABC+A(bar).BC

                  = ABC+A.B(bar).C+AB.C(bar)+A(bar).BC

Hence Y= ABC+A.B(bar).C+AB.C(bar)+A(bar).BC