Convert the Iodoform into ethyne.
Answers
Answered by
0
Answer:
What happens is that the C-I bond being weak, the iodide group is attacked by the silver atom (similar to what Na does in Wurtz reaction). As, there are 3 I-atoms and 2 molecules of iodoform usually react, 6 silver atoms are used up in the reaction and they precipitate out 6 molecules of AgI. The 2 carbon atoms form a triple bond to form acetylene.
EDIT-
2CHI3+6Ag⟶C2H2+6AgI
C−I+2Ag+I−C⟶I⋅⋅⋅Ag+Ag⋅⋅⋅I+C⋅⋅⋅C
As there are 3 C-I bonds, 6 Ag atoms form bonds with I-atoms, Hence, triple bond is formed between the 2 C-atoms. I hope that explains it.
Similar questions