convert the value of energy 10joule into a system of which 100g, 100cm, and 1min act as the fundamental units
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Adityaadi3233
02.08.2017
Physics
Secondary School
+13 pts
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Find the value of 60 joule/minute on a system which has 100g, 100cm and 1min as fundamental units.
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skyfall63
skyfall63 Ace
Answer:
\frac{60 \text { joules }}{\min }=2.16 \times 10^{6} \ \text{in new unit}
Given:
1 unit mass of defined system = 100 g
1 unit length of defined system = 100 cm
1 unit time of defined system = 1 min
Solution:
The fundamental units according to given question, the system is given with 100 g, 100 cm and 1 minutes. Unit conversion is required.
Thereby, 60 Joules per minute = n units
\frac{60 \text { joules }}{\text { minutes }}=\mathrm{n}
\frac{60 \text { joules }}{60 \text { seconds }}=\mathrm{n}
\frac{1 \text { joules }}{\text { second }}=\mathrm{n}
\frac{1 \text { joules }}{\text { second }}=1 \mathrm{kg} \mathrm{m}^{2} \text { sec }^{-3}
1 \mathrm{kg} \mathrm{m}^{2} \sec ^{-1}=\mathrm{n}(100 \mathrm{g})(100 \mathrm{cm})^{2}(1 \mathrm{min})^{-3}
1\left(\frac{1 \mathrm{kg}}{100 \mathrm{g}}\right)\left(\frac{1 \mathrm{m}}{100 \mathrm{cm}}\right)^{2}\left(\frac{1 \mathrm{sec}}{1 \mathrm{min}}\right)^{-3}=\mathrm{n}
1\left(\frac{1000 \mathrm{g}}{100 \mathrm{g}}\right)\left(\frac{100 \mathrm{cm}}{100 \mathrm{cm}}\right)^{2}\left(\frac{1 \mathrm{sec}}{60 \mathrm{sec}}\right)^{-3}=\mathrm{n}
1(10 \mathrm{g})\left(\frac{1 \mathrm{sec}}{60 \mathrm{sec}}\right)^{-3}=\mathrm{n}
1(10 \mathrm{g})(60 \mathrm{sec})^{3}=\mathrm{n}
10 \times 216000=\mathrm{n}
2.16 \times 10^{6}=\mathrm{n}
\frac{60 \text { joules }}{\min }=2.16 \times 10^{6} \ \text{in new unit}