Question

Convert to Fahrenheit scale
1. 47.5°C
2. 40°C
3. 93°C


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Answer 1

$\large{ \sf{ \purple{ \underline{ \underline{Required \: Answer :}}}}}$

Here, we have to convert Celsius (°C) scale into Fahrenheit scale (°F).

1. 47.5°C
2. 40°C
3. 93°C

So, let's solve the numericals one by one!

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Formula used :

For converting Celsius scale to Fahrenheit scale, formula is given by :-

• $\underline{ \underline {\boxed{ \rm{^{\circ}F = \bigg(^{\circ}C \times \dfrac{9}{5} \bigg) + 32}}}}$

Here,

• °F is the temperature in Fahrenheit.
• °C is the temperature in Celsius.

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$\large\bf{ \frak{ \pink{ \underline{ \underline{{(1)}}}}}}$

$\bullet$ Celsius scale (°C) is given → 47.5 °C

As we know that,

• ${\boxed{ \gray{ \bf{^{\circ}F = \bigg(^{\circ}C \times \dfrac{9}{5} \bigg) + 32}}}}$

Putting the values,

$\longrightarrow \sf ^{\circ}F = \bigg(47.5 \: \times \dfrac{9}{5} \bigg) + 32$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf ^{\circ}F = \bigg({ \cancel{47.5}} \: \times \dfrac{9} {\not{5}} \bigg) + 32$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf ^{\circ}F = (9.5 \times 9 )+ 32$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf ^{\circ}F = 85.5 + 32$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow {\red{\rm ^{\circ}F = 117.5 \: ^{\circ}F}}$

Therefore,

• 47.5 °C is equal to 117.5 °F.

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$\large\bf{ \frak{ \pink{ \underline{ \underline{{(2)}}}}}}$

$\bullet$ Celsius scale (°C) is given → 40 °C

As we know that,

• ${\boxed{ \gray{ \bf{^{\circ}F = \bigg(^{\circ}C \times \dfrac{9}{5} \bigg) + 32}}}}$

Putting the values,

$\longrightarrow \sf ^{\circ}F = \bigg(40\: \times \dfrac{9}{5} \bigg) + 32$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf ^{\circ}F = \bigg({ \cancel{40}} \: \times \dfrac{9} {\not{5}} \bigg) + 32$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf ^{\circ}F = (8 \times 9 )+ 32$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf ^{\circ}F = 72 + 32$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow {\red{\rm ^{\circ}F = 104 \: ^{\circ}F}}$

Therefore,

• 40°C is equal to 104°F.

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$\large\bf{ \frak{ \pink{ \underline{ \underline{{(3)}}}}}}$

$\bullet$ Celsius scale (°C) is given → 93°C

As we know that,

• ${\boxed{ \gray{ \bf{^{\circ}F = \bigg(^{\circ}C \times \dfrac{9}{5} \bigg) + 32}}}}$

Putting the values,

$\longrightarrow \sf ^{\circ}F = \bigg(93 \: \times \dfrac{9}{5} \bigg) + 32$

⠀⠀

$\longrightarrow \sf ^{\circ}F = \bigg({ \cancel{93}} \: \times \dfrac{9} {\not{5}} \bigg) + 32$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf ^{\circ}F = (18.6 \times 9 )+ 32$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow \sf ^{\circ}F = 167.4 + 32$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$\longrightarrow {\red{\rm ^{\circ}F = 199.4 \: ^{\circ}F}}$

Therefore,

• 93°C is equal to 199.4°F

Answer 2

${\boxed{\underline{\tt{\orange{Required \: \: answer:-}}}}}$

★GIVEN:-

• 47.5°C

• 40°C

• 93°C

These are in °C

★TO FIND:-

• Convert then into Fahrenheit.

★FORMULA USED:-

$\displaystyle \sf{F = \frac{9}{5}C + 32 } \\ \\ \displaystyle \sf{F = 1.8C + 32 }$

★SOLUTION:-

$\displaystyle \sf{(1.) \: 47.5 \degree \: C } \\ \\ : \longrightarrow \displaystyle \sf{1.8( \pink{47.5}) + 32} \\ \\ \: : \longrightarrow \displaystyle \sf{85.5 + 32} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: { \boxed{ \underline{ \pink{ \sf{ \bf{ \huge{117.5 \: F}}}}}}}$

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$\displaystyle \sf{(2.) \: 40 \degree \: C } \\ \\ : \longrightarrow \displaystyle \sf{1.8( \purple{40}) + 32} \\ \\ \: : \longrightarrow \displaystyle \sf{72 + 32} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: { \boxed{ \underline{ \purple{ \sf{ \bf{ \huge{104\: F}}}}}}}$

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$\displaystyle \sf{(3.) \: 93 \degree \: C } \\ \\ : \longrightarrow \displaystyle \sf{1.8( \blue{93}) + 32} \\ \\ \: : \longrightarrow \displaystyle \sf{167.4 + 32} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: { \boxed{ \underline{ \blue{ \sf{ \bf{ \huge{199.4\: F}}}}}}}$

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