Chemistry, asked by sudipbudhathoki286, 5 days ago

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1. Take about 5 gram of the given mixture Cuso4, and NaCl in beaker and add minimum amount of water to dissolve it.

2. Add bench NaOH solution little by little at a time with constant stirring the mixture. A bluish white precipitate forms. Allow the solution to stand for some time.

3 Test the completion of precipitation by adding few drops of NaOH to supernatant liquid. If bluish white precipitate is observed on the clear solution then add little more volume of NaOH, to make the precipitation complete.

4. Heat the mixture in a beaker for some time until bluish white mixture changes to black.

5. Filter off the content. Black precipitate of CuO is obtained as reside. Wash the black residue with hot water till it is free from Cl- and SO4--.

6. Check purity by adding few drops of AgNO3 solution and BaCl2 solution separately in two test tubes containing few ml of residue washed water. If white precipitate is obtained in both test tubes, then wash the black residue with warm water for several times.

7. Transfer the precipitate in a porcelain basin by making hole in filter paper using glass rod and dissolve in minimum quantity of H2SO4 the blue solution of Cuso4 forms, filter and evaporate the CuSO4 solution up to crystallization point.

8. After reaching crystallization point remove the basin from flame and place over the beaker full of ice water to get crystals of blue vitriol.​

Answers

Answered by llAestheticKingll91
7

Explanation:

Transfer the precipitate in a porcelain basin by making hole in filter paper using glass rod and dissolve in minimum quantity of H2SO4 the blue solution of Cuso4 forms, filter and evaporate the CuSO4 solution up to crystallization point

Answered by βαbγGυrl
1

Answer:

• Molar mass of Sodium (Na) = 5.85g/mol

• Molar mass of Chlorine (Cl) = 35.5g/mol

• Molar mass of Hydrogen (H) = 1g/mol

• Molar mass of Oxygen (O) = 16g/mol

Hence, molar mass of NaCl :-

= 23+35.5

= 58.5g/mol

And, molar mass of water [H2O] :-

= 2×1+16

= 18g/mol

Number of mole in 5.85g of Nacl :-

= Given Mass/Molar mass

= 5.85/58.5

= 0.1 mole

Number of mole in 90g of water :-

= Given Mass/Molar mass

= 90/18

= 5 mole

Mole fraction of Nacl :-

= Mole of Nacl/Total mole in solution

= 0.1/[0.1+5]

= 0.1/5.1

= 0.02

Thus, mole fraction of Nacl is 0.02 .

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