Question

convert value of G=6.67×10^-8 dyne cm^2/g^2 into SI units with the help of dimensions​

Answer 1

Answer:

G = 6.67 × 10^-11 N m^2 kg^-2

Explanation:

The dimension of G = (MLT^-2 × L^2)/M^2

= M^-1L^3T^-2

So, putting the S.I units,

S.I unit of G = Kg^-1 m^3 s^-2

= [(m s^-2) m^2]/kg

= [(kg m s^-2) m^2]/kg^2

= [N m^2]/kg^2

= N m^2 kg^-2

Now, 1 N = 10^5 dyne

1 m = 10^2 cm

1 kg = 10^3 g

So, G = 6.67 × 10^-8 dyne cm^2 g^-2 = 6.67 × 10^-8 × 10^-5 × 10^-4 × 10^6 N m^2 kg^-2

= 6.67 × 10^-11 N m^2 kg^-2

Hence, converted.