Question

convet:1-i in the polar form​

Answer 1

Answer:

tan inverse -1

hope this will help u

Answer 2

Answer:

modulus of z = r = root of 1^2 + 1^2

= root of 2

= root 2

THETA(ANGLE) LIES IN 4TH QUADRANT

argument of z= ( tan^-1 (b/a) + 2 pi)

= ( tan^-1 (-1/1) +2 pi)

= (-tan^-1 (1) +2 pi)

= ( -pi/4 +2pi)

= (7pi/4)

therefore, polar form= r (cos theta + isin theta)

=root 2( cos 7pi/4 + isin 7pi/4)

HOPE THIS HELPS YOU

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