Convex and concave lenses are kept close to each other. Magnitude of their powers are in ratio 3:5. If effective focal length is 60 cm and if it acts like a concave lens, find the focal lengths of individual lenses.
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Given:
- Magnitude of their powers are in ratio 3:5
- Effective focal length is 60 cm.
To find:
The focal lengths of the individual lenses.
Solution:
1) The power of the lenses must be 3x and -5x so the effective power of the combination will be -2x.
2) The effective focal length is 60 cm and power = 1/ focal length
- -2x = -1/60
- x = 1/120
- 3x = 1/40
- 5x = 1/24
3) The focal length of the convex lens is 40 cm and concave lens is -24 cm.
The focal lengths of the individual lenses are +40 cm and -24 cm.
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