Question

COOH
Number of oxalic acid molecules in 100 ml
COOH
of 0.02 N oxalic acid are
(1) 6.023 x 10^20 (2) 6.023 x 10^21
(3) 6.023 x 10^22 (4) 6.023× 10^23​

Answer 1

Answer:

molarity = 0.02/2= 0.01 M

Explanation:

moles of oxalic acid = 100×0.01×10^-3

=10^-3

number of oxalic acid molecules = 6.022×10^20