Coor Evaluate lim 22x 3x 39 20 2
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Answer:
Step-by-step explanation:
lim
x→a
3a+x
−2
x
a+2x
−
3x
lim
x→a
a+2x
−
3x
a+2x
+
3x
a+2x
+
3x
3a+x
−2
x
1
3a+x
+2
x
3a+x
+2
x
lim
x→a
[(3a+x)−4x]
[(a+2x)−3x]
⋅
a+2x
+
3x
3a+x
+2
x
lim
x→a
(3a−3x)
(a−x)
⋅
a+2x
+
3x
3a+x
+2
x
lim
x→a
3
1
⋅
a+2x
+
3x
3a+x
+2
x
=
3
1
(
3a
+
3a
)
(
4a
+2
a
)
=
3
1
⋅
3
2
=
3
3
2
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