Question

Coordinate of centriod of triangle with vertices (-1,3),(6,-3) and (-3,6)

Answer 1

$\large{\underline{\sf{\blue{Given-}}}}$

• Coordinates Of Centroid Of triangle are : (-1,3), (6,-3), (-3,6)

$\large{\underline{\sf{\</strong><strong>orange</strong><strong>{</strong><strong>To</strong><strong> </strong><strong>\</strong><strong>:</strong><strong> </strong><strong>Find</strong><strong>-}}}}$

• Values of the Coordinates.

$\large{\underline{\sf{\red{Solution-}}}}$

We know that,

$\boxed{\sf\green{★ Coordinates </strong><strong>\</strong><strong>:</strong><strong> </strong><strong>Of </strong><strong>\</strong><strong>:</strong><strong> </strong><strong>Centroid</strong><strong> </strong><strong>\</strong><strong>:</strong><strong> </strong><strong> </strong><strong>Of</strong><strong> </strong><strong>\</strong><strong>:</strong><strong> </strong><strong> Triangle = \frac{x_1 + x_2 + x_3}{3} , \frac{y_1 + y_2 + y_3}{3}}}$

Substituting Values,

$\leadsto\sf{ \frac{ - 1 + 6 - 3}{3} </strong><strong>,</strong><strong> </strong><strong>\: \frac{3 - 3 + 6}{3} </strong><strong>}$

$\leadsto\sf{ \frac{ - 1 + 3}{3} </strong><strong>,</strong><strong> </strong><strong>\: \frac{3 + 3}{3} }$

$\leadsto\sf{\frac{\cancel{2}}{\cancel{3}} </strong><strong>,</strong><strong> </strong><strong>\: \frac{\cancel{6}}{\cancel{3}} }$

$\boxed{\sf\purple{★ \: \frac{2}{3} </strong><strong>,</strong><strong> \: 2}}$

Hence,

• Values of the Coordinates of traingle with the vertices is ⅔ & 2.