Question

coordinates of point P and Q are negative 3 and 6 respectively then find distance PQ​

Answer 1

Given : coordinates of point P and Q are -3 and 6 respectively  

To Find :  find distance PQ​

Solution:

P = -3

Q = 6

d(PQ) = | Q - P |

= | 6 - (-3)|

=| 9 |

= 9

Hence distance PQ​ is 9

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