Coordinates of the foci of the ellipse
5x2 +9y2 +10x - 36y -4 = 0 are
A) (1, 2) and (-3,2)
B) (2, 1) and (-3,2)
C) (1, 2) and (3, 2)
D) none of these
Answers
Answered by
1
the coordinates of the foci are (1 , 2) & (- 3 , 2) for 5x² + 9y² + 10x - 36y - 4 =0
Step-by-step explanation:
5x² + 9y² + 10x - 36y - 4 =0
=> (√5x + √5)² - 5 + (3y - 6)² - 36 - 4 =0
=> (√5x + √5)² + (3y - 6)² = 45
=> (√5x + √5)² /45 + (3y - 6)²/45 = 1
=> (x + 1)²/9 + (y - 2)²/5 = 1
=> (x + 1)²/3² + (y - 2)²/(√5)² = 1
Comparing with
(x - h)²/a² + (y - k)²/b² = 1
h = - 1 , k = 2 a² = 9 b² = 5
c² = a² - b² = 9 - 5 => c = ±2
the coordinates of the foci are ( h ± c , k)
(1 , 2) & (- 3 , 2)
Learn more:
Find the equation of the ellipse coordinates of whose foci are (±2, 0 ...
https://brainly.in/question/2842122
Similar questions