Physics, asked by shagunr796, 9 months ago

coordinates of the given point P are (2,3,-1) OP is normal to the. required plane so direction ratios of the normal to the plane 2,3,-1 so equation of the plane through (2,3-1) is a(x -2)+b(y-3) +c (z+1) =0 since, the direction ratio of the normal to the plane are 2,3,-1 so we have a/2= b/3 = c/-1 hence, the equation of the required plane 2(x-2) +3(y-3) -1(z +1)=0​

Answers

Answered by bhubneshwarprasad29
0

Answer:

5353955848 +45676678- hygh

Explanation:

so it is

Similar questions