Question

coordinates of the point on y-axis which is at a distance of 7 units from co-ordinate (4,5)​

Answer 1

Answer:

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Answer 2

let yaxis coordinates be p(0,y)

A(4,5)and distance is 7units

Ap=√(4-0)^2+(y-5)^2

7=√16+(y-5)^2

squaring both sides

49=16+y^2-10y

49-16=y^2-10y

33=y^2-10y