Coordinator of a school decided to ha maximum number of mixed section a team. Each section has to accommodate equal number of boys and equal number of girls. What is the maximum number of such sections if there are 525 boys and 645 girls?
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Answer:
31 Section of 12 Boys
37 Section of 12 Girls
12 sections each with 31 Boys & 37 Girls
Step-by-step explanation:
372 boys and 444 girls
To find Equal number of boys or girls in a section we need to find HCF
372 = 2 * 2 * 3 * 31
444 = 2 * 2 * 3 * 37
31 Section of 12 Boys
37 Section of 12 Girls
Or we can have 12 sections each with 31 Boys & 37 Girls
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