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In triangle ABC, AO and BO are the angle bisectors of A and B respectively.
Find the value of x
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Step-by-step explanation:
Since AO and BO are angle bisectors,
∠1 = ∠2 --------------- (1)
∠3 = ∠4 ---------------- (2)
In ΔABC, sum of all angles = 180°
∠1 + ∠2 + ∠3 + ∠4 + 45° = 180
=> 2∠1 + 2∠3 = 135° ( from ( 1 ) and (2) )
=> ∠1 + ∠3 = 135°/2 -------------- (3)
In ΔAOB,
//sum of all angles is 180°
∠1 + ∠3 + 360 - x = 180°
=> 135°/2 + 360 - 180 = x° ( from (3))
=> 135°/2 + 180° = x°
=> x° = 495°/2 = 247.5°
=>
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