Physics, asked by roshankinholkar969, 1 day ago

COP of reversible heat pump is 1.25. If it is reversed to run as reversible heat engine, then its efficiency is

options:
a) 0.25
b) 1.25
c) 0.626
d) 0.8​

Answers

Answered by kalapuji2203
0

Explanation:

I don't know but I'm pretty sure the answers is c?

Answered by archanajhaasl
0

Answer:

The efficiency of heat engine is 0.8 i.e.option(d).

Explanation:

The COP of the reversible heat pump is given as,

COP=\frac{1}{\eta}        (1)

Where,

COP=coefficient of performance of heat pump

η=efficiency of Carnot engine

From the question we have,

COP=1.25

By substituting the value of COP in equation (1) we get;

1.25=\frac{1}{\eta}

\eta=\frac{1}{1.25}

\eta=0.8

Hence, the efficiency of heat engine is 0.8 i.e.option(d).

#SPJ2

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