Copper acetate formula by criss cross method
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Explanation:
Given:
Mass, m = 5kg
Initial Velocity, u = 20m/s
Final Velocity, v = 0.20m/s
Find:
Change In Momentum
Solution:
we, know that
\underline{ \boxed{ \pink{ \sf Δ p = m(v - u)}}}
Δp=m(v−u)
where,
m = 5kg
v = 0.20m/s
u = 20m/s
So,
\sf \to Δ p = m(v - u)→Δp=m(v−u)
\sf \to Δ p = 5(0.20 - 20)→Δp=5(0.20−20)
\sf \to Δ p = 5( - 19.8)→Δp=5(−19.8)
\underline{ \boxed{ \blue{ \sf \to Δ p = - 99kg \: m/s}}}
→Δp=−99kgm/s
Hence, change in momentum of the body will be -99kg m/s
The - ve sign indicates that there is a decrease in the momentum of the body.
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