Question

Copper block of 3.1 kg is heated in a furnace from 20 degree Celsius to 520 degree Celsius and then placed on thick ice box. calculate specific heat of copper is mass of ice melted is 1.8 kg. (given= latent heat of fusion of ice = 333 kJ/kg.)​ as possible soon​

Answer 1

Answer:

Specific heat capacity of copper is 371.8 J/kg C

Explanation:

Here we know that when copper block is placed on the ice block then heat given to the ice is used to melt it

so here we can say by energy balance

Heat loss by copper block = Heat absorbed by the ice

So we will have

$m_{copper} s \Delta T = m_{ice} L$

so we have

$3.1 s (520 - 0) = 1.8(333 \times 10^3)$

$1612 s = 599400$

$s = 371.8 J/kg ^oC$

#Learn

Topic : Calorimetry

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