Question

Copper combines with oxygen to form two oxides. 0.716 gram of
copper [I] oxide contains 0.636 gram of copper. 0.398 gram of
copper [II] oxide contains 0.318 gram of copper. Prove that,
these data illustrate the law of multiple proportions.

Answer 1

Answer:

ANSWER

Let the two oxides of Cu be named A and B

oxide A

mass of Cu in 1g of oxide A = 0.888g

mass of O in 1g of oxide A =1-0.888=0.112g

oxide B

mass of Cu in 1g of oxide B = 0.799g

mass of O in g of oxide B = 1-0.799=0.201g

In oxide A , 1g Cu is combined with oxygen = 0.112 x 1/0.888 = 0.126g

In oxide B , 1g Cu is combined with oxygen = 0.201 x 1/0.799 = 0.252g

the different weight of oxygen combined with a fixed weight (1g) of Cu are in ratio 0.126: 0.252 or 1: 2

This is a simple whole ratio that shows the agreement with the law of multiple properties.

Explanation:

I think this will help you

Answer 2

Answer:

Let the two oxides of Cu be named A and B

oxide A

mass of Cu in 1g of oxide A = 0.888g

mass of O in 1g of oxide A =1-0.888=0.112g

oxide B

mass of Cu in 1g of   oxide B = 0.799g

mass of O in g of oxide B = 1-0.799=0.201g

In oxide A , 1g Cu is combined with oxygen = 0.112 x 1/0.888 = 0.126g

In oxide B , 1g Cu is combined with oxygen = 0.201 x 1/0.799 = 0.252g

the different weight of oxygen combined with a fixed weight (1g) of Cu are in ratio 0.126: 0.252  or 1: 2

This is a simple whole ratio that shows the agreement with the law of multiple properties