Question

copper crystallises in a fcc units cell with cell edge of 3.608 cm and its density is 8.92 g cm-3 calculate the atomic mass of copper

Answer 1

Answer:

Given :

Side length of the unit cell = 3.608×10⁻⁸ cm

Density of the unit cell = 8.92 g/cm³

To Find :

The atomic mass of copper

Solution :

In FCC lattice the number of atoms present in one unit cell = 4

The atomic mass of the element is given by the relation

                      M=\frac{dN_{A}a^{3} }{z}M=zdNAa3

By substituting the values in the above relation,

                      M=\frac{8.92\times6.023\times 10^{23}(3.608\times10^{-8})^{3} }{4}M=48.92×6.023×1023(3.608×10−8)3

                      M=63.1 g/molM=63.1g/mol

 The atomic mass of copper is 63.1 g/mol

Explanation:

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