Question

Copper crystallises into fcc structure and the unit cell has length of edge 3.61 x 10⁻⁸ cm. Calculate the density of copper if the molar mass of Cu is 63.5g mol (8.92 g cm⁻³)

Answer 1

For the FCC lattice Z= 4

However, the atomic mass (M) = 63.5

And a = 3.61x10-8

Therefore if we consider the formula density = Z x M/a3 x N0

Hence, the density = (4 x 63.5)/(3.61 x 10^-8 x 6.022  x 10^23) =  8.96 gcm-3.

Hence, the value will be 8.92 for the density.  

Answer 2

Answer:

Explanation:

d=z*M/a^3*6.023*10^23

d= 4*63.5/(3.61*10^-8)^3*6.023

d=254/28.3

d=8.97