Question

Copper crystallizes in fcc lattice the edge length of its unit cell is 3.608*10^-8cm calculate the density of crystal given atomic mass of copper= 63u

Answer 1

Copper crystallizes in fcc lattice the edge length of its unit cell is 3.608*10^-8cm calculate the density of crystal given atomic mass of copper= 63u

Answer 2

Correct question :

Copper crystallizes in fcc lattice the edge length of its unit cell is $\rm{3.61\times{}10^{-8}\:cm.}$ Calculate the density of copper (given M = 63.5).

Answer :

• Density of copper = 8.87 g/cm³.

Step-by-step explanation :

Given that,

• Edge length, a = $\rm{3.61\times{}10^{-8}\:cm}$

Also,

• For fcc lattice, Z = 4.
• Molar mass of copper = 63.5 g/mol.
• Avogadro's number = $\rm{6.023\times{}10^{23}\:mol^{-1}}$

$\hrulefill$

We know, $\rm{\rho=\dfrac{Z\times{}M}{a^3\times{}N_0}}$

Putting the given values, we get,

$\rm{Density=\dfrac{4\times{}63.5\:g\:mol^{-1}}{(3.61\times{}10^{-8}\:cm)^3\times{}6.023\times{}10^{23}\:mol^{-1}}}$

Solving, we get,

$\rm{Density=}\:\bold{8.97\:g\:cm^{-3}}$