Question

Copper forms two oxides. For the same amount of copper, twice as much oxygen
was used to form the first oxide than to form the second one. What is the ratio
of the valencies of copper in the first and second oxides?

Here, what does it mean by the ratio of valencies of copper in first n second oxide???

I didn't need the whole solution just give me the explanation of the last line.​

Answer 1

Answer:

Copper form two oxides i.e. CuO and Cu 2 O.

First oxide – CuO

Molecular weight of copper = 63.5

Molecular weight of oxygen = 16

Here, 63.5 parts of copper reacts with 16 parts of oxygen.

 

Second oxide – Cu2O

Molecular weight of copper =63.5×2=127

Molecular weight of oxygen = 16

Here, 63.5 parts of copper reacts with 8 parts of oxygen.

 

Hence, ratio of valencies of first copper oxide to other =16:8=2:1

Explanation: