Copper gives two oxide . On heating 1.0 g of each in hydrogen gas
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HEY MATE!!
let the two oxides of Cu be named A and B
oxide A
mass of Cu in 1g of oxide A = 0.888g
mass of O in 1g of oxide A =1-0.888=0.112g
oxide B
mass of Cu in 1g of oxide B = 0.799g
mass of O in g of oxide B = 1-0.799=0.201g
In oxide A , 1g Cu is combined with oxygen = 0.112 x 1/0.888 = 0.126g
In oxide B , 1g Cu is combined with oxygen = 0.201 x 1/0.799 = 0.252g
the different weight of oxygen combined with a fixed weight (1g) of Cu are in ratio 0.126 : 0.252 or 1: 2
This is a simple whole ratio that shows the agree with the law of multiple properties .
HOPE IT HELPS!
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