Copper gives two oxides. On heating 1.0gm of each
in hydrogen gas, 0.888gm and 0.799gm of the metals are produced.show that the results agree with the law of multiple proportion.
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In the compound that yields 0.888 g of Cu, the remainder of the 1 g must by O, so that would be 0.112 g O. The parts of Cu that combine with 1 part of O =0.888/0.112 = 7.93
In the compound that yields 0.799 g of Cu, the remainder of the 1 g must be O, so that would be 0.201 g. The parts of Cu that combine with 1 part of O = 0.799/0.201 = 3.98.
The ratio of Cu that combines with a fixed mass of O is 7.93:3.98 or 2:1.
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