Copper has an atomic radius of 0.128 nm, an FCC crystal structure, and an atomic weight of 63.5 g/mol. Compute its theoretical density and compares the answer with its measured density.
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Copper has an atomic radius of 0.128 nm, an FCC crystal structure, and an atomic weight of 63.5 g/mol. Compute its theoretical density and compares the answer with its measured density.
Solution :
Atomic radius of copper = 0.128 nm
Atomic weight of copper = 63.5 g/mol
¶ = ZM / a3NA
Z = 4 ( for fCC)
M = 63.5 g ( for Cu)
a = 2√2r
{ Putting the value of r }
= 2√2 × 0.128 nm
= 2√2×0.128×10-⁹ m
N.A= 6.022×10²³
______________________
Now we are giving the value in the equation :-
=> 4×63.5 / ( 2√2×0.128×10-⁹)³ × 6.022 × 10²³
=> 8.89 g / cm³
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