Chemistry, asked by joshmatum906, 8 months ago

Copper(II) carbonate is broken down by heating to form copper(II) oxide and carbon dioxide gas. The equation for the reaction is shown. CuCO3 → CuO + CO2 31.0g of copper(II) carbonate are heated until all of the contents of the test-tube have turned from green to black. The yield of copper(II) oxide formed is 17.5g. What is the percentage yield?

Answers

Answered by lisajungkookie
9

Answer:

hmmm i think you should divide 17.5 by 31 and multiply that by hundred.... :D

Explanation:

Answered by adhithinkangeya
8

Answer:

56.50%

Explanation:

precentage yield = actual yield/predicted yield * 100

17.5/31 * 100 = 56.45 (round off to 56.50)

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