Question

Copper (II) chloride reacts with lead to form a solution of lead chloride and Copper.​

Answer 1

Correct Question:-

Convert the following text equation to symbolic format. (Also, balance it.)

Answer:-

Copper (II) = ${Cu}^{2+}$

Chloride = ${Cl}^{-}$

∴ Copper Chloride = $CuCl_2$

Lead (II) = ${Pb}^{2+}$

∴ Lead Chloride = $PbCl_2$

So, our equation (skeletal equation) would be:-

$\boxed{ CuCl_2 \ (s) + Pb \ (s) \longrightarrow PbCl_2 \ (l) + Cu \ (s) }$

We can observe that, the equation follows law of conservation of mass, i.e. number of atoms before reaction and after reaction are same. Therefore, it is the balanced equation.