Chemistry, asked by zeyadrahoma10, 2 months ago

. Copper (II) oxide reacts with dilute hydrochloric acid. Cuo(s) + 2HCl(aq) → Cuci (aq) + H2O(1) 6.00 g of copper (II) oxide were added to 50.0 cm of 1.00 mol/dm3 hydrochloric acid. This was an excess of copper (II) oxide. (a) i) Calculate the number of moles of copper(II)oxide added to the hydrochloric acid. (ii) Calculate the number of moles of hydrochloric acid used. (iii) Calculate the no of moles of copper(II) oxide that react with 0.05 moles of HCI​

Answers

Answered by lmachowski072008
1

Answer:

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Answered by Anonymous
7

Explanation:

Given ,

Current (I) = 0.5 A

Time , t = 10 × 60 s = 600 s.

Charge , Q= It = 0.5 A × 600 s

= 300 C.

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