Science, asked by paulodybalafan89, 9 months ago

Copper on corrosion gives a product. Its compost is what?
Please help.

Answers

Answered by drchandankumar52
1

Answer:

it's copper carbonate , CuCo3

Answered by saxenakamini745
1

Answer:

Corrosion is usually defined as the degradation of metals due to an electrochemical process. The formation of rust on iron, tarnish on silver, and the blue-green patina that develops on copper are all examples of corrosion. The total cost of corrosion in the United States is significant, with estimates in excess of half a trillion dollars a year.

The Statue of Liberty is a landmark every American recognizes. The Statue of Liberty is easily identified by its height, stance, and unique blue-green color (Figure 1). When this statue was first delivered from France, its appearance was not green. It was brown, the color of its copper “skin.” So how did the Statue of Liberty change colors? The change in appearance was a direct result of corrosion. The copper that is the primary component of the statue slowly underwent oxidation from the air. The oxidation-reduction reactions of copper metal in the environment occur in several steps. Copper metal is oxidized to copper(I) oxide (Cu2O), which is red, and then to copper(II) oxide, which is black

2

Cu

(

s

)

+

1

2

O

2

(

g

)

Cu

2

O

(

s

)

(

red

)

Cu

2

O

(

s

)

+

1

2

O

2

(

g

)

2

CuO

(

s

)

(

black

)

2Cu(s)+12O2(g)Cu2O(s)(red)Cu2O(s)+12O2(g)2CuO(s)(black)

Coal, which was often high in sulfur, was burned extensively in the early part of the last century. As a result, sulfur trioxide, carbon dioxide, and water all reacted with the CuO

2

CuO

(

s

)

+

CO

2

(

g

)

+

H

2

O

(

l

)

Cu

2

CO

3

(

OH

)

2

(

s

)

(

green

)

3

CuO

(

s

)

+

2

CO

2

(

g

)

+

H

2

O

(

l

)

Cu

2

(

CO

3

)

2

(

OH

)

2

(

s

)

(

blue

)

4

CuO

(

s

)

+

SO

3

(

g

)

+

3

H

2

O

(

l

)

Cu

4

SO

4

(

OH

)

6

(

s

)

(

green

)

2CuO(s)+CO2(g)+H2O(l)Cu2CO3(OH)2(s)(green)3CuO(s)+2CO2(g)+H2O(l)Cu2(CO3)2(OH)2(s)(blue)4CuO(s)+SO3(g)+3H2O(l)Cu4SO4(OH)6(s)(green)

These three compounds are responsible for the characteristic blue-green patina seen today. Fortunately, formation of the patina created a protective layer on the surface, preventing further corrosion of the copper skin. The formation of the protective layer is a form of passivation,

Similar questions