Chemistry, asked by notnyet1234, 11 months ago

Copper sulphate on treatment potassium iodide precipitates to form cuprous iodide iodine gas and also forms potassium sulphate.

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Answered by mananmadani53
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Answer:

Explanation: The reaction of copper sulfate in aqueous state and potassium iodide in solid state produces cuprous iodide as a precipitate, liberates iodine gas and forms potassium sulfate in aqueous state.

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