Science, asked by ayushpatel5779, 6 months ago

copper sulphate on treatment with potassium iodide precipitate cuprous oxide, liberates iodine gas and also form potassium sulphate.

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Answered by devip649

Answer. Explanation: The reaction of copper sulphate in aqueous state and potassium iodide in solid state produces cuprous iodide as a precipitate, liberates iodine gas and forms potassium sulfate in aqueous state

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copper sulphate on treatment with potassium iodide precipitate cuprous oxide, liberates iodine gas and also form potassium sulphate.​

Answers

❤❤BTS ARMY FOREVER❤❤

KHS

copper sulphate on treatment with potassium iodide precipitate cuprous oxide, liberates iodine gas and also form potassium sulphate.