Chemistry, asked by kaushalarjun221, 5 months ago

Copper sulphate on treatment with potassium iodide precipitates cuprous
iodide (Cuz 12), liberates iodine gas and also forms potassium sulphate.​

Answers

Answered by jurimahanta
3

Answer:

2CuSO4 + 4KI→2CuI + I2  + 2K2 SO4

​

Explanation:

The reaction of copper sulphate in aqueous state and potassium iodide in solid state produces cuprous iodide as a precipitate, liberates iodine gas and forms potassium sulfate in aqueous state.

The balanced chemical equation is:

2CuSO4+4Kl gives rise to 2K2SO4+CU2I2+I2

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