Question

Copper sulphate on treatment with potassium iodide precipitates cuprous iodide libretes iodine gas and also forms potassium sulphate write rhe balanced chemical equation

Answer 1

2CuSO4+4Kl gives rise to 2K2SO4+CU2I2+I2
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Answer 2

Explanation: The reaction of copper sulfate in aqueous state and potassium iodide in solid state produces cuprous iodide as a precipitate, liberates iodine gas and forms potassium sulfate in aqueous state.

The balanced chemical equation is:

$2CuSO_4(aq.)+4KI(s)\rightarrow Cu_2I_2(s)+2K_2SO_4(aq.)+I_2(g)$

By stoichiometry,

2 moles of copper sulfate reacts with 4 moles of potassium iodide produces 1 mole of cuprous iodide, 2 moles of potassium sulfate and 1 mole of iodine gas.