Question

Copper sulphate reacts with sodium hydroxide to form a blue precipitate of copper hydroxide and sodium sulphate. In an experiment, 15.95 g of copper sulphate reacted with 8.0 g of sodium hydroxide to form 9.75 g of copper hydroxide and 14.2 g of sodium sulphate. Which law of chemical combination is illustrated by this data ? Give reason for your choice. Class 9th
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Answer 1

Explanation:

The law of conservation of mass is illustrated by this data.

The mass of products = The mass of reactants

CuS

O

4

+ NaOH → Cu

(

O

H

)

2

+ NaS

O

4

(15.95 g) (8 g) (9.75 g) (14.2 g)

Total mass of reactants = (15.95 g + 8 g) = 23.95 g

Total mass of products = (9.75 g + 14.2 g) = 23.95 g

Hence, Law of conservation of mass is valid here.

Answer 2

Explanation:

The law of conservation of mass is illustrated by this data.

The mass of products = The mass of reactants

CuSO4 + NaOH → Cu(OH)2 + NaSO4

(15.95 g) (8 g) (9.75 g) (14.2 g)

Total mass of reactants = (15.95 g + 8 g) = 23.95 g

Total mass of products = (9.75 g + 14.2 g) = 23.95 g

Hence, Law of conservation of mass is valid here.