Copper sulphate solution is electrolysed between two platinum electrodes. a current is passed until 1.6 g of oxygen is liberated at anode. the amount of copper deposited at the cathode during the same period is
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Solved Examples on Electrochemistry
Example 1.
Find the charge in coulomb on 1 g-ion of N3-.
Solution:
Charge on one ion of N3-
= 3 × 1.6 × 10-19 coulomb
Thus, charge on one g-ion of N3-
= 3 × 1.6 10-19 × 6.02 × 1023
= 2.89 × 105 coulomb
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Example 2.
How much charge is required to reduce (a) 1 mole of Al3+ to Al and (b)1 mole of to Mn2+ ?
Solution:
(a)
Example 1.
Find the charge in coulomb on 1 g-ion of N3-.
Solution:
Charge on one ion of N3-
= 3 × 1.6 × 10-19 coulomb
Thus, charge on one g-ion of N3-
= 3 × 1.6 10-19 × 6.02 × 1023
= 2.89 × 105 coulomb
______________________________________________________________________________
Example 2.
How much charge is required to reduce (a) 1 mole of Al3+ to Al and (b)1 mole of to Mn2+ ?
Solution:
(a)
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Copper sulphate solution is electrolysed between two platinum electrodes. A current is passed until 1.6 g of oxygen is liberated at anode. The amount of copper deposited at the cathode during the same period is: (a) 6.36 g (b) 63.68 (c) 12.7 g (d) 3.2 g.
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