Question

Copper sulphate solution on mixing with ammonia (ratio 1:4 for cu2+ ions but of sulphate ion. Explain.) does not exhibit test

Answer 1

Iron sulphate does not shape any complex with (NH4)SO4. Rather, they structure a twofold salt, FeSO4.(NH4)2SO4.6H2O (Mohr's salt) which separates finished in particle in the arrangement. Consequently, it gives the trial of Fe2+ particles. Copper sulfate arrangement blended with watery alkali in 1 : 4 molar proportion shapes the complex with the equation [Cu(NH3)]SO4 in which the mind boggling particle, [Cu(NH3)4]2+ does not separate to give Cu2+ particles. Consequently, it doesn't give the tests of Cu2+ particle.