Question

Copper wire when bent in the form of a square in closed and area of 484 cm square the same wire is bent to form a circle find area enclosed by the circumstances

Answer 1

THE AREA OF SQUARE =484

SIDE=$\sqrt{484}$

SIDE=22

AREA OF CIRCLE=$\pi$ R SQUARE THEN R=22 THEN FURTHER SOLVE IT :-p TOOK POINTS OH YEAHH!!!!!!!!!!

Answer 2

Let each side of a square be x cm and radius of the circle be r cm

Area of the square = $\sf{{484cm}^{2}}$

$\therefore$ $\sf{ {x}^{2} = 484 = x = 22cm}$

$\therefore$ Perimeter of the square

= 22 × 4 = 88cm = Length of the wire

= Circumference of the circle, when the same wire is bent in the form of a circle

= 2πr = 88

= $\sf{r=\frac{44}{π}}$

$\therefore$ Area of the circle =

= $\sf{\pi \times \frac{44}{\pi} \times \frac{44}{\pi} = \frac{44}{22} \times 7 \times 44}$

= $\sf{ {616cm}^{2}}$